Section 3.6 Problem 1 Details

The diagram above shows the ray passing through the point (-4,3). The angle we want to find is labeled A. Note that,

and that -B is the angle between the positive x-axis, and the ray through (4,-3). The same reasoning will work for any point like (-4,3). Thus, since -B = arctan(-3/4), we discover that for any point lying in the second quadrant, the angle we seek is given by arctan(y/x) +. Doing the same analysis for a point in the third quadrant shows that in this case the angle is also given by arctan(y/x) +.

If the x coordinate of a point is negative, it must lie in either the second or third quadrant. Hence, for a point (x,y) with x negative, the angle is given by arctan(y/x) +. Otherwise, if x is positive, the point lies in quadrant one or four, and thus the angle already lies in the range . Hence in this case, arctan(y/x) is already the angle we want.

Of course, if the point lies on the y-axis, i.e. if it is of the form (0,y), then the expression arctan(y/x) is undefined. However, in this special case, it is clear the angle is , where the sign depends on the sign of y.


OU Math Study Group, Copyright 1995.
Last modified: Sun Sep 10 16:24:25 1995